## Monday, November 26, 2007

*Son, I can't count past 100 but I know that.*

*If you divide the number of eggs by 2 there will be one egg left.*

*If you divide the number of eggs by 3 there will be one egg left.*

*If you divide the number of eggs by 4 there will be one egg left.*

*If you divide the number of eggs by 5 there will be one egg left.*

*If you divide the number of eggs by 6 there will be one egg left.*

*If you divide the number of eggs by 7 there will be one egg left.*

*If you divide the number of eggs by 8 there will be one egg left.*

*If you divide the number of eggs by 9 there will be one egg left.*

*If you divide the number of eggs by 10 there will be one egg left.*

*Finally. If you divide the Number of eggs by 11 there will be NO EGGS left!*

__Solutions:__

Read the solutions only after making a genuine attempt in solving the above puzzles.

1.This puzzle is a classic one which has no solution in 2D. However, if you place the items on a doughnut shape in 3D you can solve it. In the picture below, E is linked to 3 by going over the top and re-entering through the hole in the middle.

2.We have to be careful what we are adding together. Originally, they paid £30, they each received back £1, thus they now have only paid £27. Of this £27, £25 went to the manager for the room and £2 went to the bellboy.(This puzzle was used in a tamil film Rassaiyah for a comedy scene involving vadivel!!!)

3.25,201 eggs.

This puzzle has a few different methods for finding the solution, one of which is:

Find a number X into which all of the numbers from 2 to 10 divide evenly. You can do this by simply using 2*3*4*5*6*7*8*9*10, but you can find a smaller number by finding the prime factors, a subset of which can be used to form any number from 2 to 10. 2*2*2*3*3*5*7 will do. This comes out to be 2520, and is the lowest number into which all the numbers 2-10 divide evenly.

We can add 1 to this number to satisfy the first 9 constraints of the puzzle (the remainder of 2521/2, 2521/3 ... 2521/10 is one), but this does not satisfy the last constraint, divisibility by 11.

Fortunately, we can multiply X (=2520) by any integer and add 1 and we will still satisfy constraints 1-9. So what Y do we multiply X by so that (X*Y) + 1 is divisible by 11. 2520/11 has a remainder of 1. Thus two 2520s divided by eleven would have a remainder of 1+1 = 2, and so forth...so ten 2520s divided by 11 would have a remainder of 10. This number plus one would divide eleven evenly, as well as also satisfy the first 9 constraints - thus 25201 is the answer.

Hope you liked these puzzles...

Puzzles were taken from:http://www.brainbashers.com/

Labels: Puzzles

## 12 comments:

you spend a lot of tie bloggin dude !!! and always hav lots of information for fellow blooggers!!!

hmmm ya zahid...I do spend a lot of time blogging...And I learn lot of information by blogging...

Like i said before superb blog..i like all the trivia and all....

thanks dude....

too mind-wrenching. period. will be back when i ve the time, and the right nerves.. :D this is a well maintained blog, btw, good goin..

thannks gauri.....

havve a look at my other posts too...

I love this site!

Thanks steve...

nice puzzles dude!!!

thanks dude....

your mystery blog is cool too....

Great puzzles....between cn u tel me a site frm whr we can download torrents??

www.torrentz.com

is the best site dude....

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